Beta

Same force, different handle lengths

Rotate the same inertia from rest under the same force. Compare angle and speed for different handle lengths on one time axis.

Diagram and inputs ↓

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Same effort, a longer handle

Assume 9.80665 N, equivalent to a 1 kg weight, pushing perpendicular at the end.

Handle lengths share one scale. Results are torque, not rotational speed or tool strength.

More numeric references and examples

Compare values with everyday references

Baseline: 1 kg-equivalent perpendicular force at 10 cm gives about 0.98 N·m

Compare values and familiar conditions, then apply a representative example.

Push a 10 cm handleAbout 0.981 N·m

Perpendicular force equivalent to 1 kg weight at 10 cm; the same torque needs half the force at 20 cm.

Push a 20 cm handleAbout 1.961 N·m

Perpendicular force equivalent to 1 kg weight at 20 cm; the same torque needs half the force at 40 cm.

Push a 20 cm handleAbout 9.807 N·m

Perpendicular force equivalent to 5 kg weight at 20 cm; the same torque needs half the force at 40 cm.

More references (2)

Push a 5 cm handleAbout 0.245 N·m

Perpendicular force equivalent to 0.5 kg weight at 5 cm; the same torque needs half the force at 10 cm.

Push a 30 cm handleAbout 14.71 N·m

Perpendicular force equivalent to 5 kg weight at 30 cm; the same torque needs half the force at 60 cm.

Reference conditions

Assumes a perpendicular effort. The button sets the stated representative length and force; these are not specified tightening torques.

Visual preview

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2D · front view of the rotation plane

Playback speed

0.00 sReveal animation

T=Fr sinβ, α=T/I, φ=αt²/2. Frictionless, massless handle, fixed load inertia. Applied force follows the handle at fixed angle β. Ending the observation does not mean rotation stops.

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Conditions

Input unit

T=Fr sinβ, α=T/I, φ=αt²/2. Frictionless, massless handle, fixed load inertia. Applied force follows the handle at fixed angle β. Ending the observation does not mean rotation stops.

Motion conditions and equations

Conditions represented by this motion

T=Fr sinβ, α=T/I, φ=αt²/2. Frictionless, massless handle, fixed load inertia. Applied force follows the handle at fixed angle β. Ending the observation does not mean rotation stops.

Load inertia I is shared while handle length changes. Handle inertia, friction and controllers are excluded. At 1×, one elapsed second equals one simulated second; other playback scales are labeled.

From tightening torque to axial force

1. Match the unitsTorque unit converter →
2. Calculate with the required inputsBolt tightening torque and axial force →
3. See the motion or differenceTorque and lever armCurrent page

Also supply bolt diameter and torque coefficient. The coefficient depends on friction and lubrication.

Each tool opens with its own conditions. Values are not transferred automatically.

Same force, different handle lengths

Same effort, a longer handle

Compare values with everyday references

Visual preview

Conditions

Motion conditions and equations

Related tools

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