Match the diagram conditions, then follow the example inputs and results. Change numerical values in the calculator.
1. Match the diagram to your question
右へ動く物が、緩衝材に当たって停止する例です。停止距離は実際に減速する距離です。
質量m・接触前の速度v・停止距離sを入力します。物体の全長をsにはしません。
止める運動
水平に移動する物を止める
移動物の質量 m
10 kg
接触直前の速度 v
1 m/s
接触後に停止するまでの距離 s
20 mm
橙のFは停止距離全体に対する平均の力です。瞬間の最大力とは違います。
平均接触力（ピークではありません）
250 N
接触後に吸収するエネルギー
5 J
一定減速度と仮定した停止時間
0.04 s
A right-moving load stops against a buffer. Stopping distance is the actual deceleration travel.
Enter mass m, impact speed v and stopping travel s. Object length is not s.
Motion being stopped
Stop horizontal motion
Moving mass m
10 kg
Speed just before contact v
1 m/s
Stopping distance after contact s
20 mm
Orange F is average force over stopping travel, not the instantaneous peak.
Average contact force, not peak
250 N
Energy absorbed after contact
5 J
Stopping time assuming constant deceleration
0.04 s
Blue marks inputs; orange marks outputs. These diagrams explain the fixed example below; dimensions and deformation are not drawn to physical scale.
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2. Example inputs
Motion being stoppedWhat goes here?
Choose the option matching your mechanism and diagram. A different model can change required inputs and applicable results.
Stop horizontal motion
Moving mass mWhat goes here?
This is mass, including fixtures or loads that move with it where required. Kilograms describe mass; newtons describe force.
10 kg
Speed just before contact vWhat goes here?
Distance travelled per time. Check whether the field asks for initial, final or constant speed.
1 m/s
Stopping distance after contact sWhat goes here?
Use the dimension marked in the diagram. Distinguish radius from diameter, bore from outside diameter, and overall length from support span.
20 mm
These are fixed teaching inputs. Coefficients, properties and comparison limits are not recommendations. Enter your conditions in the calculator.
3. Results for this example
Average contact force, not peak
250 N
Energy absorbed after contact
5 J
Stopping time assuming constant deceleration
0.04 s
This is linear stopping. The 250 N result is average contact force, not instantaneous peak force. Stopping time additionally assumes constant deceleration.
4. Which formula is used?
E = mv²/2; Favg = E/s; t = 2s/v
Table units are not always the units required in the formula. The calculator converts selected units to its internal base units before computing.
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Assumptions and exclusions
Contact force averaged by work over the stopping distance. Peak force, contact stiffness and force history cannot be determined from mass, speed and distance alone. Drop mode starts from rest and includes gravitational work during stopping. Constant deceleration is used only for the illustrative time estimate.
