Match the diagram conditions, then follow the example inputs and results. Change numerical values in the calculator.
1. Match the diagram to your question
質量が異なる2つの部品を並べた例です。基準位置を同じ座標でそろえます。
各部品の質量と、その部品の重心のx・y・zを入力します。外形の端ではありません。
駆動へ渡す軸
z軸
指定軸が通る点 x
0 mm
指定軸が通る点 y
0 mm
指定軸が通る点 z
0 mm
部品1 · m1, x1, y1, z1
10 kg · (0, 0, 0) mm
部品2 · m2, x2, y2, z2
5 kg · (200, 0, 0) mm
橙のGが全体の重心です。重い方へ寄ります。この例では原点から約66.7 mmです。
合計質量
15 kg
G · x̄ · 重心 x
66.6667 mm
選択した駆動軸の慣性
0.2 kg·m²
Two components with different masses share one coordinate reference.
Enter each component’s mass and centroid x, y, z, not its outside edge.
Axis for drive transfer
z axis
Axis point x
0 mm
Axis point y
0 mm
Axis point z
0 mm
Component 1 · m1, x1, y1, z1
10 kg · (0, 0, 0) mm
Component 2 · m2, x2, y2, z2
5 kg · (200, 0, 0) mm
Orange G is the combined centroid, closer to the heavier part: about 66.7 mm from the origin here.
Total mass
15 kg
G · x̄ · Centre x
66.6667 mm
Selected drive-axis inertia
0.2 kg·m²
Blue marks inputs; orange marks outputs. These diagrams explain the fixed example below; dimensions and deformation are not drawn to physical scale.
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2. Example inputs
Axis for drive transferWhat goes here?
Choose the direction of the axis for inertia J. Centre coordinates x, y and z are calculated independently.
z axis
Axis point xWhat goes here?
Use the dimension marked in the diagram. Distinguish radius from diameter, bore from outside diameter, and overall length from support span.
0 mm
Axis point yWhat goes here?
Use the dimension marked in the diagram. Distinguish radius from diameter, bore from outside diameter, and overall length from support span.
0 mm
Axis point zWhat goes here?
Use the dimension marked in the diagram. Distinguish radius from diameter, bore from outside diameter, and overall length from support span.
0 mm
Example components, with zero intrinsic centroidal inertia
Mass
x
y
z
10 kg
0 mm
0 mm
0 mm
5 kg
200 mm
0 mm
0 mm
These are fixed teaching inputs. Coefficients, properties and comparison limits are not recommendations. Enter your conditions in the calculator.
3. Results for this example
Total mass
15 kg
Centre x
66.6667 mm
Selected drive-axis inertia
0.2 kg·m²
Heavier components have a greater influence. Here 10 kg at x=0 and 5 kg at x=200 mm give a combined centre at x≈66.7 mm.
4. Which formula is used?
c = Σ(mi ci)/Σmi; Jz(O) = Σ[Jzi + mi((xi−ox)²+(yi−oy)²)]
Table units are not always the units required in the formula. The calculator converts selected units to its internal base units before computing.
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Assumptions and exclusions
1–30 parts. Each intrinsic Jx/Jy/Jz is about its own centre, parallel to the assembly axes. Zero uses a point-mass approximation. No orientation tensor rotation is performed.
